A solution of urea (molar mass 56 g/mol) boils at 100.18°C at the atmospheric pressure. If Kf and Kb of water are 1.86 and 0.52 K kgmol−1 respectively, the above solution will freeze at
−0.654∘ C
ΔTf=kf×m and ΔTb=kb×m
ΔTfΔTb=KfKb and Given ΔTb=0.18∘C
Hence ΔTf=1.860.512×0.18=0.654
∴ Tf=0−0.654∘ C=−0.654∘ C