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Question

A solution of y=2x(dydx)+x2(dydx)4 is

A
y=2c12x14+c
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B
y=2cx2+c2
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C
y=2c(x+1)
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D
y=2cx+c2
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Solution

The correct option is D y=2cx+c2
Write p=dydx and differentiating w.r.t.x, we have
p=2p+2xdpdx+2xp4+4p4+4p3x2dpdx0=p(1+2xp3)+2x(1+2p3x)p+2xdpdx=02dpdx=dxx2logp+logx=constp2x=c or p=cx
Substituting this value in the given equation, we get y=2cx+c2

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