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Raoult's Law

A solution wa...

Question

A solution was made by dissolving 2 g of a solute in 100 g of acetone. The solution boiled at 56.95° C. The boiling point of pure acetone is 55.95° C, and the K_b =1.71°C/m. What is the molecular weight of the solute?

22 g

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34.2 g

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42.3 g

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30 g

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Solution

The correct option is B
34.2 g

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Similar questions

{100.34}^{\circ} C

K_{b}

= {0.52}^{\circ} C / m

{100.34}^{\circ} C

K_{b}

= {0.52}^{\circ} C / m

152

^{- 1})

{56.3}^{\circ} C

{56.55}^{\circ} C

{56.46}^{\circ} C .

61^{\circ} C .

{64.63}^{\circ} C .

K_{b} = 3.63 {K kg mol}^{- 1},

56^{\circ} C

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