A solution which is 10^-3 M each in Mn²⁺, Fe²⁺, Zn²⁺ and Hg²⁺ is treated with 10^-16 M sulphide ion. If K_sp of MnS, FeS, ZnS and HgS are 10^-15, 10^-23, 10^-20 and 10^-54 respectively, which one will precipitate first?

Q. A solution is

10^{- 3} M

each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

and

H g^{2 +}

is treated with

10^{- 16} M

sulphide ion.If

K_{s p}

values of MnS, Fes, ZnS and HgS are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

Q. A solution which is

10^{- 3} N

each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

and

H g^{2 +}

is treated with

10^{- 16} M

sulphide ion. If

K_{s p}

values of

M n S, F e S, Z n S

and

H g S

are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first ?

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A solution which is 10−3M each in Mn2+,Fe2+,Zn2+ and Hg2+ is treated with 10−16M sulphide ion. If Ksp of MnS,FeS,ZnS and HgS are 10−13,10−18,10−24 and 10−53 respectively, which one will precipitate first?

The correct option is B HgSAccording to given data, [S2−] needed for precipitation ofFeS=10−1810−3=10−15MMnS=10−1310−3=10−10MHgS=10−5310−3=10−50MZnS=10−2410−3=10−21MThus, minimum [S2−] is for HgS and so it will be precipitated first.

A solution which is $10^{- 3} M$ each in ${M n}^{2 +}, {F e}^{2 +}, {Z n}^{2 +}$ and ${H g}^{2 +}$ is treated with $10^{- 16} M$ sulphide ion. If $K_{s p}$ of $M n S, F e S, Z n S$ and $H g S$ are $10^{- 13}, 10^{- 18}, 10^{- 24}$ and $10^{- 53}$ respectively, which one will precipitate first?