You visited us 96 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Werner's Coordination Theory

A solution wh...

Question

A solution which is $10^{- 3}$ M each in $M n^{2 +}, F e^{2 +}, Z n^{2 +} a n d H g^{2 +}$ is treated with $10^{- 16}$ M sulphide ion. If $K_{s p}$ of MnS, FeS, ZnS, and HgS are $10^{- 15}, 10^{- 23}, 10^{- 20} a n d 10^{- 54}$ respectively, which one will precipitate first?

FeS

No worries! We‘ve got your back. Try BYJU‘S free classes today!

MgS

No worries! We‘ve got your back. Try BYJU‘S free classes today!

HgS

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

ZnS

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C HgS
$Salt having low K_{s p} precipitates first. Thus HgS will precipitate first.$

Suggest Corrections

Similar questions

Q. A solution which is

10^{- 3} M

each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

, and

H g^{2 +}

is treated with

10^{- 16} M

sulphide ion. If the

K_{s p}

M n S, F e S, Z n S

and

H g S

are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

Q. A solution is

10^{- 3} M

each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

and

H g^{2 +}

is treated with

10^{- 16} M

sulphide ion.If

K_{s p}

values of MnS, Fes, ZnS and HgS are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

Q. A solution which is

10^{- 3} M

each in

{M n}^{2 +}, {F e}^{2 +}, {Z n}^{2 +}

and

{H g}^{2 +}

is treated with

10^{- 16} M

sulphide ion. if

K_{s p}

M n S, F e S, Z n S

and

H g S

are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

Q. A solution which is

10^{- 3}

M each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

and

H g^{2 +}

is treated with

10^{- 16}

M sulphide ion. If

K_{s p}

M n S, F e S, Z n S

and

H g S

are

10^{- 15}, 10^{- 25}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

A solution which is 10^-3 M each in Mn²⁺, Fe²⁺, Zn²⁺ and Hg²⁺ is treated with 10^-16 M sulphide ion. If K_sp of MnS, FeS, ZnS and HgS are 10^-15, 10^-23, 10^-20 and 10^-54 respectively, which one will precipitate first?

Join BYJU'S Learning Program

A solution which is 10−3M each in Mn2+,Fe2+,Zn2+ and Hg2+ is treated with 10−16M sulphide ion. If Ksp of MnS, FeS, ZnS, and HgS are 10−15,10−23,10−20and 10−54 respectively, which one will precipitate first?

The correct option is C HgSSalt having low Ksp precipitates first. Thus HgS will precipitate first.

A solution which is $10^{- 3}$ M each in $M n^{2 +}, F e^{2 +}, Z n^{2 +} a n d H g^{2 +}$ is treated with $10^{- 16}$ M sulphide ion. If $K_{s p}$ of MnS, FeS, ZnS, and HgS are $10^{- 15}, 10^{- 23}, 10^{- 20} a n d 10^{- 54}$ respectively, which one will precipitate first?

The correct option is C HgS
$Salt having low K_{s p} precipitates first. Thus HgS will precipitate first.$