A sonar device fitted in a submarine receives an echo $4 s$ later the signal is transmitted towards another submarine $3060 m$ away. Find the speed of sound in water.

1530 m s^{- 1}

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1342 m s^{- 1}

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1600 m s^{- 1}

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1250 m s^{- 1}

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Solution

The correct option is B $1530 m s^{- 1}$
Distance between two submarines, $s = 3060 m$
Time taken by signal to go from sonar to another submarine, $t = \frac{4}{2} s = 2 s$
$∴$ velocity of sound in water $= \frac{s}{t} = \frac{3060}{2} m s^{- 1} = 1530 m s^{- 1}$

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Similar questions

A sonar device on a submarine sends out a signal and receives an echo $5 s$ later. Calculate the speed of sound in water if the distance of the object from the submarine is $3625 m$ .

Q. Question 20
A sonar device on a submarine sends out a signal and receives an echo 5 s later. Calculate the speed of sound in water if the distance of the object from the submarine is 3625 m.

A SONAR system fixed in a submarine operates at a frequency 40.0 kHz. An enemy submarine moves towards the SONAR with a speed of 360 km h^–1. What is the frequency of sound reflected by the submarine? Take the speed of sound in water to be 1450 m s^–1.

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A sonar device fitted in a submarine receives an echo 4s later the signal is transmitted towards another submarine 3060m away. Find the speed of sound in water.

The correct option is B 1530ms−1Distance between two submarines, s=3060mTime taken by signal to go from sonar to another submarine, t=42s=2s∴ velocity of sound in water =st=30602ms−1=1530ms−1

A sonar device fitted in a submarine receives an echo $4 s$ later the signal is transmitted towards another submarine $3060 m$ away. Find the speed of sound in water.

The correct option is B $1530 m s^{- 1}$
Distance between two submarines, $s = 3060 m$
Time taken by signal to go from sonar to another submarine, $t = \frac{4}{2} s = 2 s$
$∴$ velocity of sound in water $= \frac{s}{t} = \frac{3060}{2} m s^{- 1} = 1530 m s^{- 1}$