Question

A sonometer wire of density d and radius r is held between two bridges at a distance L apart. The wire has a tension T. The fundamental frequency of the wire will be

• A. $f=\frac{1}{2Lr}\sqrt{\frac{T}{\pi d}}$
• B. $f=\frac{1}{2L}\sqrt{\frac{\pi d}{T}}$
• C. $f=\frac{1}{2Lr}\sqrt{\frac{d}{\pi T}}$
• D. $f=\frac{1}{2L}\sqrt{\frac{d}{T}}$

Answer 1

The correct option is A

$f=\frac{1}{2Lr}\sqrt{\frac{T}{\pi d}}$

$f=\frac{v}{2L}=\frac{1}{2L}\sqrt{\frac{T}{\pi r^{2}d}}$