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Standard IX

Physics

Pitch

A sound sourc...

Question

A sound source of frequency 512 Hz is producing 6 beats with a guitar. If the string of the guitar is stretched slightly then beat frequency decreases. The original frequency of guitar is

506 Hz

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512 Hz

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518 Hz

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524 Hz

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Solution

The correct option is A 506 Hz
Given,

Frequency of sound source =512 Hz

Number of beats = 6

As the string of the guitar is slightly stretched, the beat frequency decreases.

So,

The original frequency of the guitar = Frequency of sound source - Number of beats

$= 512 - 6 = 506 H z$

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A sound source of frequency 512 Hz is producing 6 beats with a guitar. If the string of the guitar is stretched slightly then beat frequency decreases. The original frequency of guitar is

The correct option is A 506 HzGiven,Frequency of sound source =512 HzNumber of beats = 6As the string of the guitar is slightly stretched, the beat frequency decreases.So,The original frequency of the guitar = Frequency of sound source - Number of beats=512−6=506Hz

The correct option is A 506 Hz
Given,

Frequency of sound source =512 Hz

Number of beats = 6

As the string of the guitar is slightly stretched, the beat frequency decreases.

So,

The original frequency of the guitar = Frequency of sound source - Number of beats

$= 512 - 6 = 506 H z$