A sound wave of frequency 100 Hz is travelling in air. The speed of sound in air is 350 m s $^{- 1}$ . By how much is the phase changed at a given point in 2.5 ms?

$π$

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$\frac{3 π}{5}$

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$\frac{π}{2}$

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$0.2 π$

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Solution

The correct option is C
$\frac{π}{2}$

The change in phase is given by $ω t, Δ Φ$

$= 2 π f t = 2 π \times 100 \times 2.5 \times 10^{- 3}$

$= \frac{π}{2}$

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A sound wave of frequency 100 Hz is travelling in air. The speed of sound in air is $350 m s^{- 1}$ . (a) By how much is the phase changed at a given point in 2.5 ms? (b) What is the phase difference at a given instant between two points separated by a distance of 10.0 cm along the direction of propagation?

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What is the phase difference at a given instant between two points separated by a distance of 10.0 cm along the direction of propagation?

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A sound wave of frequency 100 Hz is travelling in air. The speed of sound in air is 350 m s−1. By how much is the phase changed at a given point in 2.5 ms?

The correct option is C π2 The change in phase is given by ωt, ΔΦ =2πft=2π×100×2.5×10−3 =π2

A sound wave of frequency 100 Hz is travelling in air. The speed of sound in air is 350 m s $^{- 1}$ . By how much is the phase changed at a given point in 2.5 ms?

The correct option is C
$\frac{π}{2}$

The change in phase is given by $ω t, Δ Φ$

$= 2 π f t = 2 π \times 100 \times 2.5 \times 10^{- 3}$

$= \frac{π}{2}$