A sound wave of frequency 100 Hz is travelling in air. The speed of sound in air is 350 m s−1.
What is the phase difference at a given instant between two points separated by a distance of 10.0 cm along the direction of propagation?
2π35
General expression for pressure is time for sound is
P=P0 sin ω(t−xv)
P=P0sin (ωt−ωxv)
If some phase Φ is present initially then that gets added up
P=P0 sin (ωt−ωxv+Φ)
Lets say Φ was 0 when particle was at X0 at time to
So equation become P=P0 sin (ωt0−ωx0v)
Now the same equation for a particle at a point 10 cm from x0 at same time to
P=P0 sin (ωt0−ω(x0+0.1)v)
⇒P=P0 sin (ωt0−ωx0vω0.1v)
So here phase is Φ=ω0.1v
Given f=100 Hz
ω=2πf=200π
v=350 m/s
Φ=200π×1×10−1350=2π35
OR
2π
Phase change is given by ΔΦ=kx=2πxλ
λ=vf
350100=3.5 m
Therefore, ΔΦ=2π(0.1)3.5=2π35