A sound wave of frequency 440 Hz- is passing through air- An O2 molecule mass -5-3- 10-26 kg- is set in oscillation with an amplitude of 10-6 m- Its speed at the centre of its oscillation is-

Two particles A and B of masses 1 kg and 2 kg respectively are kept 1 m apart and are released to move under mutual attraction. Find the speed of A when that of B is 3 cm/hour. What is the separation between the particles at this instant?

Q. Charge passes through a conductor of cross section at area

A = 0.3 m^{2}

is given by

q = 3 t^{2} + 5 t + 2

in coloumb, where t is in second. What is the value of drift velocity at t = 2 sec (given n =

2 \times 10^{25} / m^{2}

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A sound wave of frequency 440 Hz, is passing through air. An O2 molecule mass =5.3×10−26 kg, is set in oscillation with an amplitude of 10−6 m. Its speed at the centre of its oscillation is:

The correct option is C 2.76×10−3 m/sGiven, frequency(f) of sound wave is 440Hz Amplitude of wave is A=10−6mWe know that speed at the Centre of oscillation is =ωA=2πfASubstitute all value in above equation =2×3.14×440×10−6=2.76×10−3m

A sound wave of frequency $440 H z$ , is passing through air. An $O_{2}$ molecule mass $= 5.3 \times 10^{- 26} k g$ , is set in oscillation with an amplitude of $10^{- 6} m$ . Its speed at the centre of its oscillation is: