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Question

A sound wave of wavelength 32 cm enters the tube as shown in the figure. Then the smallest radius r so that a maximum of sound is heard at detector is :

9319_36d8d82260bd4e5d8eebb14d76203646.png

A
7 cm
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B
14 cm
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C
21 cm
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D
28 cm
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Solution

The correct option is D 28 cm
For max sound two waves need to interfere constructively.
Path difference for the waves has to be integer multiple of wavelength.
Path length =S1=πr
Path length =S2=2r
Path difference =Δx=S1S2=πr2r=nλ
For min radius, n=1
πr2r=1×λ
r(π2)=λ
r×1.14=32
r=321.14=28cm

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