A source and an observer move away from each other with a velocity of $10 m / s$ with respect to ground. If the observer finds the frequency of sound coming from the source as $1950 H z$ , then actual frequency of the source is (Velocity of sound in air $= 340 m / s$ )

1950 H z

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2068 H z

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2132 H z

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2486 H z

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Solution

The correct option is B $2068 H z$
$\begin{matrix} A c c o r d i n g t o q u e s t i o n . . . . . F = F_{0} [\frac{c - v_{R}}{c + v_{S}}] ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} w h e r e F = o b s e r v e d f r e q u e n c y F_{0} = e m i t t e d f r e q u e n c y, c = v e l o c i t y o f w a v e s v_{R} = o b s e r v e r i s o v i n g f r o m t h e s o u r s e . v_{S} = s o u r c e i s m o v i n g t o s o u r c e \end{matrix} \Rightarrow F_{0} = F [\frac{c + v_{S}}{c - v_{R}}] = 1950 \times [\frac{340 + 10}{340 - 10}] = 1950 \times \frac{350}{330} = 2068 H z s o t h a t t h e c o r r e c t o p t i o n i s B . \end{matrix}$

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