A source and listener are moving towards each other with the speed of 54 km/hr. If the true frequency of sound emitted by the source is $500 H z$ , calculate the observed frequency when both source and listener are moving towards each other. Velocity of sound in air = $330 m s^{- 1}$ .

547.62 Hz

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447.62 Hz

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475.26 Hz

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754.26 Hz

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Solution

The correct option is A 547.62 Hz
Given:
True frequency, $f = 500 H z$
Velocity of sound, $v_{s} = 54 k m / h r = \frac{54 \times 1000}{60 \times 60} = 15 m / s$
Source and observer moving towards each other
Therefore, Apparent frequency is given by
$f^{'} = \frac{v + v_{0}}{v - v_{s}} f = \frac{330 + 15}{330 - 15} \times 500 = \frac{345 \times 500}{315} = 547.62 H z$

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A source and listener are moving towards each other with the speed of 54 km/hr. If the true frequency of sound emitted by the source is 500Hz, calculate the observed frequency when both source and listener are moving towards each other. Velocity of sound in air = 330ms−1.

The correct option is A 547.62 HzGiven: True frequency, f=500HzVelocity of sound, vs=54km/hr=54×100060×60=15m/sSource and observer moving towards each otherTherefore, Apparent frequency is given by f′=v+v0v−vsf=330+15330−15×500=345×500315=547.62Hz

A source and listener are moving towards each other with the speed of 54 km/hr. If the true frequency of sound emitted by the source is $500 H z$ , calculate the observed frequency when both source and listener are moving towards each other. Velocity of sound in air = $330 m s^{- 1}$ .