A source of light is placed at a distance 4m from a photocell and the stopping potential is then 7.7 volt. If the distance is halved, the stopping potential now will be:
A
7.7 volt
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B
15.4 volt
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C
3.85 volt
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D
1.925 volt
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Solution
The correct option is C 7.7 volt Stopping potential is independent of distance between light source and photocell. So, stopping potential will be 7.7 volt only.