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Standard X

Physics

Doppler Effect

A source of s...

Question

A source of sound A emitting waves of frequency 1800 Hz is falling towards ground with a terminal speed v. The observer B on the ground directly beneath the source receives wave of frequency 2150hz. The source A receives waves, reflected from frequency nearly: (Speed of sound = 343 m/s)

2150 Hz

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2500Hz

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1800Hz

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2400Hz

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Solution

The correct option is D 2500Hz
Frequency received by source A is
$f = 1800 (\frac{343 + V}{343 - V})$
$f o r V;$
$2150 = 1800 (\frac{343}{343 - V})$
$343 - V = \frac{1800 \times 343}{2150}$
$V = 56 m / s$
$∴ f = 1800 (\frac{399}{287}) ≃ 2500 H z$

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A source of sound A emitting waves of frequency 1800 Hz is falling towards ground with a terminal speed v. The observer B on the ground directly beneath the source receives wave of frequency 2150hz. The source A receives waves, reflected from frequency nearly: (Speed of sound = 343 m/s)

The correct option is D 2500HzFrequency received by source A isf=1800(343+V343−V)forV;2150=1800(343343−V)343−V=1800×3432150V=56m/s∴f=1800(399287)≃2500Hz

The correct option is D 2500Hz
Frequency received by source A is
$f = 1800 (\frac{343 + V}{343 - V})$
$f o r V;$
$2150 = 1800 (\frac{343}{343 - V})$
$343 - V = \frac{1800 \times 343}{2150}$
$V = 56 m / s$
$∴ f = 1800 (\frac{399}{287}) ≃ 2500 H z$