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Question

A source of sound having frequency 2000Hr & a receiver are located at the same point at the instant t = 0, the source starts moving with const. accn(a=10m/s2).
Find the frequency registered by the receiver at the instant t = 10sr. Velocity of sound in air is 340 m/s.

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Solution

From-
v=u+at
vs=0+10×10
vs=100m/s
From the formula-
f=f(vv+vs)
f=2000(340340+100)
f=1545.45

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