A source of sound is travelling with a velocity 40 km/hr towards an observer and emits sound of frequency 2000 Hz. If velocity of sound is 1220 km/hr, then what is the apparent frequency heard by an observer?

2210 Hz

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1920 Hz

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2068 Hz

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2086 Hz

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Solution

The correct option is C 2068 Hz
$\begin{matrix} f^{'} = (\frac{v}{v - v_{s}}) f = (\frac{1220}{1220 - 40}) (2000) \approx 2068 H z \end{matrix}$
Hence,
option $(C)$ is correct answer.

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A source of sound is travelling with a velocity 40 km/hr towards an observer and emits sound of frequency 2000 Hz. If velocity of sound is 1220 km/hr, then what is the apparent frequency heard by an observer?

The correct option is C 2068 Hzf′=(vv−vs)f=(12201220−40)(2000)≈2068HzHence,option (C) is correct answer.

The correct option is C 2068 Hz
$\begin{matrix} f^{'} = (\frac{v}{v - v_{s}}) f = (\frac{1220}{1220 - 40}) (2000) \approx 2068 H z \end{matrix}$
Hence,
option $(C)$ is correct answer.