A source of sound of frequency $90 Hz$ is moving towards an observer with a velocity one-tenth the velocity of sound. The frequency heard by the observer will be :

50 Hz

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100 Hz

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200 Hz

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300 Hz

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Solution

The correct option is B $100 Hz$
$n^{'} = \frac{V}{V - V_{s}} n_{0}$ , we are given $n_{0} = 90 H z$ and $V_{s} = (1 / 10) V$

Substituting these values in the equation of Doppler's effect in sound.

$n^{'} = \frac{V}{V - (1 / 10) V} 90 = 100 H z$ .

option "B" is correct.

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A source of sound of frequency 90 Hz is moving towards an observer with a velocity one-tenth the velocity of sound. The frequency heard by the observer will be :

The correct option is B 100 Hzn′=VV−Vsn0, we are given n0=90Hz and Vs=(1/10)VSubstituting these values in the equation of Doppler's effect in sound.n′=VV−(1/10)V90=100Hz.option "B" is correct.

A source of sound of frequency $90 Hz$ is moving towards an observer with a velocity one-tenth the velocity of sound. The frequency heard by the observer will be :

The correct option is B $100 Hz$
$n^{'} = \frac{V}{V - V_{s}} n_{0}$ , we are given $n_{0} = 90 H z$ and $V_{s} = (1 / 10) V$

Substituting these values in the equation of Doppler's effect in sound.

$n^{'} = \frac{V}{V - (1 / 10) V} 90 = 100 H z$ .

option "B" is correct.