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Standard XII

Physics

Resonance in Sound Waves

A source of s...

Question

A source of sound placed at the open end of a resonance column sends an acoustic wave of pressure amplitude $P_{A}$ inside the tube. If the atmospheric pressure is $P_{0}$ then the ratio of maximum and minimum pressure at the closed end of the tube will be

$\frac{P_{A} + P_{0}}{P_{A} - P_{0}}$

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$\frac{P_{A} + 2 P_{0}}{P_{A} - 2 P_{0}}$

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$\frac{P_{A}}{P_{0}}$

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( $\frac{P_{A} + \frac{1}{2} P_{0}}{P_{A} - \frac{1}{2} P_{0}}$ )

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Solution

The correct option is A
$\frac{P_{A} + P_{0}}{P_{A} - P_{0}}$

Maximum pressure at closed end will be atmospheric pressure adding with acoustic wave pressure.

So $P_{m a x}$ = $P_{A}$ + $P_{0}$ and $P_{m i n}$ = $P_{A}$ - $P_{0}$

Thus $\frac{P_{m a x}}{P_{m i n}}$ = $\frac{P_{A} + P_{0}}{P_{A} - P_{0}}$

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Similar questions

A source of sound placed at the open end of a resonance column sends an acoustic wave of pressure amplitude $P_{A}$ inside the tube. If the atmospheric pressure is $P_{0}$ then the ratio of maximum and minimum pressure at the closed end of the tube will be

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$P = P_{0} s i n ω (t - \frac{x}{v})$

Inference:

In the tube where this wave is propagating if we measure pressure, then the maximum pressure measured will be _{$P_{0}$}atm and Minimum pressure measured will be _{$- P_{0}$}atm as maximum $&$ minimum values of sin $θ$ is (+1/-1).

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A source of sound placed at the open end of a resonance column sends an acoustic wave of pressure amplitude PA inside the tube. If the atmospheric pressure is P0 then the ratio of maximum and minimum pressure at the closed end of the tube will be

The correct option is A PA+P0PA−P0 Maximum pressure at closed end will be atmospheric pressure adding with acoustic wave pressure. So Pmax = PA + P0 and Pmin = PA - P0 Thus PmaxPmin = PA+P0PA−P0

A source of sound placed at the open end of a resonance column sends an acoustic wave of pressure amplitude $P_{A}$ inside the tube. If the atmospheric pressure is $P_{0}$ then the ratio of maximum and minimum pressure at the closed end of the tube will be