Question

A source oscillates with a frequency 25 Hz and the wave propagates with 300 m/s. Two points A and B are located at distances 10 m and 16 m away from the source. The phase difference between A and B is

• A. $\frac{\pi }{4}$
• B. $\frac{\pi }{2}$
• C. $\pi$
• D. $2\pi$

Answer 1

The correct option is C $\pi$

Wavelength of the wave=$\lambda =\frac{v}{\nu }=\frac{300}{25}=12m$

Distance between the two points=$16m-10m=6m=\frac{\lambda }{2}$

$=\frac{2\pi }{\lambda }\frac{\lambda }{2}=\pi$