A source produces $60$ rarefactions and $60$ compressions in $0.6 s$ . Distance between a compression and the next (consecutive) rarefaction is $150 c m$ . Find the frequency of the wave.

500 H z

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0.02

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0.01 H z

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100 H z

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Solution

The correct option is D $100 H z$
Distance between a compression and consecutive rarefactions is $\frac{λ}{2} = 150 c m$
So, $λ = 300 c m$
Time period $=$ time between two consecutive compression/rarefaction
$= \frac{0.6 s}{60}$ $= 0.01 s$
Frequency $= \frac{1}{T} = \frac{1}{0.01}$ $= 100 H z$

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A source produces 60 rarefactions and 60 compressions in 0.6s. Distance between a compression and the next (consecutive) rarefaction is 150cm. Find the frequency of the wave.

The correct option is D 100HzDistance between a compression and consecutive rarefactions is λ2=150cmSo, λ=300cmTime period = time between two consecutive compression/rarefaction =0.6s60=0.01sFrequency =1T=10.01=100Hz

A source produces $60$ rarefactions and $60$ compressions in $0.6 s$ . Distance between a compression and the next (consecutive) rarefaction is $150 c m$ . Find the frequency of the wave.

The correct option is D $100 H z$
Distance between a compression and consecutive rarefactions is $\frac{λ}{2} = 150 c m$
So, $λ = 300 c m$
Time period $=$ time between two consecutive compression/rarefaction
$= \frac{0.6 s}{60}$ $= 0.01 s$
Frequency $= \frac{1}{T} = \frac{1}{0.01}$ $= 100 H z$