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Standard IX

Physics

Amplitude

A sourceS of ...

Question

A source(S) of sound wave generates sound of equal intensity in all directions. If $D_{1} a n d D_{2}$ are two sound detectors placed with respect to the source as shown below, then the ratio of intensities of sound at $D_{1} a n d D_{2} i s e q u a l t o$

4:1

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2:1

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1:4

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1:2

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Solution

The correct option is C 1:4
$S D_{1} = d_{1} = 5 c m S D_{2} = d_{2} = 2.5 c m$

Intensity of the sound wave, $l \propto \frac{1}{(D i s t a n c e)^{2}}$

Ratio of intensities detected by $d e t e c t o r s D_{1} a n d D_{2} : \frac{l_{1}}{l_{2}} = {(\frac{d_{2}}{d_{1}})}^{2} = \frac{(2.5)^{2}}{(5)^{2}} \Rightarrow l_{1} : l_{2} = 1 : 4$

Hence, the correct answer is option (c).

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A source(S) of sound wave generates sound of equal intensity in all directions. If D1 and D2 are two sound detectors placed with respect to the source as shown below, then the ratio of intensities of sound at D1 and D2 is equal to

The correct option is C 1:4SD1=d1=5 cmSD2=d2=2.5 cm Intensity of the sound wave, l∝1(Distance)2 Ratio of intensities detected by detectors D1 and D2:l1l2=(d2d1)2=(2.5)2(5)2⇒l1:l2=1:4 Hence, the correct answer is option (c).

A source(S) of sound wave generates sound of equal intensity in all directions. If $D_{1} a n d D_{2}$ are two sound detectors placed with respect to the source as shown below, then the ratio of intensities of sound at $D_{1} a n d D_{2} i s e q u a l t o$