A space craft of mass $M$ is moving with velocity $V$ and suddenly explodes into two pieces. A part of it of mass $m$ becomes at rest, then the velocity of other part will be

\frac{M V}{M - m}

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\frac{M V}{M + m}

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\frac{m V}{M - m}

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\frac{(M + m) V}{m}

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Solution

The correct option is D $\frac{M V}{M - m}$
Since there is no external force, momentum would be remain conserved.
After explosion m mass comes at rest and let Rest $(M - m)$ mass moves with velocity v.
By the law of conservation of momentum
$M V = (M - m) v$
$\Rightarrow v = \frac{M V}{(m - m)}$

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A space craft of mass M is moving with velocity V and suddenly explodes into two pieces. A part of it of mass m becomes at rest, then the velocity of other part will be

The correct option is D MVM−mSince there is no external force, momentum would be remain conserved.After explosion m mass comes at rest and let Rest (M−m) mass moves with velocity v.By the law of conservation of momentum MV=(M−m)v⇒v=MV(m−m)

A space craft of mass $M$ is moving with velocity $V$ and suddenly explodes into two pieces. A part of it of mass $m$ becomes at rest, then the velocity of other part will be

The correct option is D $\frac{M V}{M - m}$
Since there is no external force, momentum would be remain conserved.
After explosion m mass comes at rest and let Rest $(M - m)$ mass moves with velocity v.
By the law of conservation of momentum
$M V = (M - m) v$
$\Rightarrow v = \frac{M V}{(m - m)}$