A spacecraft is travelling at a speed of $12$ km/sec. How much time will it take to reach the surface of the moon, If the distance between the Moon and the Earth is $3.48 \times 10^{8}$ m?

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Solution

$S p e e d = \frac{D i s t a n c e}{T i m e}$
$S p e e d = 12 k m / s e c = 12000 m / s$
$D i s t a n c e = 3.48 * 10^{8} m$
$T i m e = \frac{D i s t a n c e}{S p e e d} = \frac{3.48 * 10^{8}}{12000} = 2.9 * 10^{4} s$

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A spacecraft is travelling at a speed of 12 km/sec. How much time will it take to reach the surface of the moon, If the distance between the Moon and the Earth is 3.48×108 m?

Speed=DistanceTimeSpeed=12km/sec=12000m/sDistance=3.48∗108mTime=DistanceSpeed=3.48∗10812000=2.9∗104s

A spacecraft is travelling at a speed of $12$ km/sec. How much time will it take to reach the surface of the moon, If the distance between the Moon and the Earth is $3.48 \times 10^{8}$ m?

$S p e e d = \frac{D i s t a n c e}{T i m e}$
$S p e e d = 12 k m / s e c = 12000 m / s$
$D i s t a n c e = 3.48 * 10^{8} m$
$T i m e = \frac{D i s t a n c e}{S p e e d} = \frac{3.48 * 10^{8}}{12000} = 2.9 * 10^{4} s$