Question

A spaceship covers a distance of $4\times {10}^4$ km. What is the rate of fuel comsumption if the spaceship consumes $4.4\times {10}^5$ L of fuel?

• A. $1.1\times {10}^4{\text{cm}}^3/\text{km}$
• B. $1.1\times {10}^4{\text{L}}^3/\text{km}$
• C. $1.1\times {10}^5{\text{cm}}^3/\text{km}$
• D. $1.1\times {10}^5{\text{L}}^3/\text{km}$

Answer 1

The correct option is A $1.1\times {10}^4{\text{cm}}^3/\text{km}$

Given:
Distance covered = $4\times {10}^4$ km
Fuel consumed = $4.4\times {10}^5$ L

Rate of fuel consumption

$=\frac{\text{Amount of fuel consumed}}{\text{Distance coverd}}$

$=\frac{4.4\times {10}^5}{4\times {10}^4}$

$=\frac{4.4}{4}\times {10}^{5-4}$

$=1.1\times {10}^1\text{L/km}$

$\because 1\text{L/km}=1000{\text{cm}}^3/\text{km}$

$=1.1\times {10}^1\times 1000{\text{cm}}^3/\text{km}$

$=1.1\times {10}^4{\text{cm}}^3/\text{km}$

$\therefore$ Rate of fuel consumption is $1.1\times {10}^4{\text{cm}}^3/\text{km}$.