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Question

a specimen of hematite contains 20 percent Fe2o3 .what weight of iron can be obtained from 1000 kg of hematite

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Solution

Molecular mass of Fe2O3 = 2 × 56 + 3 × 16 = 160 g The ore contains 20 % of Fe2O3So the mass of Fe2O3 in the given sample of hematite 1000 kg = 200 gMass % of iron in Fe2O3 = 2 × 56 160 × 100 =70 %So 70 % of 200 g of Fe2O3 = 70100 × 200 = 140 g of iron

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