Question

A specimen of iron of relative permeability 2850 was introduced in a field of magnetizing force 2.0 x 10² amp/m. calculate the absolute permeability (m) and the flux density in the iron

Answer 1

. u = u_o x u_r .

• u = the permeability of the material measured in Henries per metre (Hm^-1).
• u_o = the permeability of free space measured in Henries per metre (Hm^-1).
• u_r = the relative permeability of the material (no units).

Note: the permeabilty of free space u_o is 4 PI x10^-7 H/m .
u=4pi×10^-7×2850
=11400pi×10^-7

u​​​​ =B/H

• u = the permeability of the material measured in Henries per metre (Hm^-1).
• B = flux density measured in Tesla (T).
• H = the field strength measured in Amperes per metre (Am^-1).

u =B/H
11400pi×10^-7=B/(2×10^2)
B=22800pi×10^-5
Put the value of pi
Thank you