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Question

A spectral line in the spectrum of H atom has a wavenumber of 15222.22 cm1 . The transition responsible for this radiation is (Rydberg constant R = 109677 cm1)


A

21

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B

42

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C

32

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D

23

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Solution

The correct option is C

32


Here, let recall what is wave number
J=1λλ=1¯ν

And also,
¯ν=1λ=R×Z2[1n211n22]

Therefore,
λ=1¯ν=115222.22=6.569×105cm=6569˚A (visible light wavelength)
Clearly, it lies in the visible region i.e., in Balmer series. Hence, n1=2. Using the relation for wave number for H atom,

¯ν=1λ=RZ2(1n211n22)

15222.22=109677(1221n22)

n2=3

The required transition is 32.
Hence, (c) is correct.

Note: (d) is wrong because 23 will absorb radiation


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