A sperical black body with a radius of 12 cm radiates 450 W power at 500 K. If the radius were halved and temperature be doubled, the power radiated in watt would be:
A
1800
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B
900
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C
3600
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D
850
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Solution
The correct option is A 1800 Power radiated P =Aε∼T4 P=(πr2)ε∼T4[∵A=πr2] ⟹P∝r2T4 P1P2=(r1r2)2(T1T2)4=(rr/2)2(T2T)4=14 P2=4×P1=4×450=1800W