A sphere carrying charge is just at rest without falling down touching a vertical wall, by applying a horizontal electric feld 100 $N C_{- 1}$ . The charge on the ball is 0.01 C. If the coefficient of friction between wall and sphere is 0.2, mass of the sphere is (g = 10 $m / s^{2}$ )

2 kg

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20 gm

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0.2 kg

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Solution

The correct option is B 20 gm
f = mg - - - - - - - - - - - -- (1)
N = F = Eq - - - - - - - - - - - -(2)
$μ = \frac{f}{N} = \frac{m g}{E q}$
$m = \frac{μ E q}{g} = \frac{0.2 \times 100 \times 0.0}{10}$
= 0.02 Kg
m = 20 gm

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A sphere carrying charge is just at rest without falling down touching a vertical wall, by applying a horizontal electric feld 100 NC−1. The charge on the ball is 0.01 C. If the coefficient of friction between wall and sphere is 0.2, mass of the sphere is (g = 10 m/s2)

The correct option is B 20 gmf = mg - - - - - - - - - - - -- (1) N = F = Eq - - - - - - - - - - - -(2) μ=fN=mgEq m=μEqg=0.2×100×0.010 = 0.02 Kg m = 20 gm

A sphere carrying charge is just at rest without falling down touching a vertical wall, by applying a horizontal electric feld 100 $N C_{- 1}$ . The charge on the ball is 0.01 C. If the coefficient of friction between wall and sphere is 0.2, mass of the sphere is (g = 10 $m / s^{2}$ )

The correct option is B 20 gm
f = mg - - - - - - - - - - - -- (1)
N = F = Eq - - - - - - - - - - - -(2)
$μ = \frac{f}{N} = \frac{m g}{E q}$
$m = \frac{μ E q}{g} = \frac{0.2 \times 100 \times 0.0}{10}$
= 0.02 Kg
m = 20 gm