Question

A sphere of 4 cm radius is suspended within a hollow sphere of 6cm radius. The inner sphere is charged to a potential of 3 e.s.u. When the outer sphere is earthed the charge on the inner sphere is :-

Answer 1

Answer:

Answer is 36 esu

Explanation:

Potential on outer sphere
Kq1/6 + kq2/6=0
Thus, q2=-q1
Now potential on inner sphere
3=kq1/4 + kq2/6
Substituting q2 with -q1..we get,
3= kq1/4 - kq1/6
On further solving,q1=36