You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Pseudo Force

A sphere of d...

Question

A sphere of density d is allowed to fall in a liquid of density d/4. The acceleration of the body will be:

\frac{g}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3 g}{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{g}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{3 g}{4}$

Now,
Force downward $= m g = V d g$
Net force upward $= \frac{V d g}{4}$
So,
Net force dowanward $= \frac{3}{4} V d g = m a$
$\frac{3}{4} V d g = V d a$
$a = \frac{3 g}{4}$

Suggest Corrections

Similar questions

Q. The acceleration due to gravity at a place is

g m / s^{2}

. A lead sphere of density

d k g / m^{3}

is dropped into a liquid column of density

ρ k g / m^{3}

. If

d > ρ

, then the sphere will fall down with

Q. At a given place where acceleration due to gravity is 'g

m / s^{2}

, a sphere of lead of density 'd'

k g / m^{3}

is gently released in a column of liquid of density p

k g / m^{3}

. If

d > p

, the sphere will

Q. If the acceleration due to gravity is

g m s^{- 2}

, a sphere of lead of density

δ k g / m^{3}

is gently released in a column of liquid of density

d k g / m^{3} (δ > d)

, the sphere will fall vertically with:

Q. At a given place where acceleration due to gravity is

g m / s e c^{2}

, a sphere of lead of density

d k g / m^{3}

is gently released in a column of liquid of density

ρ k g / m^{3}

. If

d > ρ

, then immediately after the sphere is released inside the liquid, it will:

A solid cylinder of height h and mass m floats in a liquid of density $ρ$ as shown in Fig. Now the cylinder is released inside a liquid of density $\frac{ρ}{4}$ , contained in a downward accelerated vessel. Determine the magnitude of acceleration of vessel(A), for which cylinder sinks with relative acceleration $\frac{A}{3}$ with respect to vessel.
Neglect any dissipative force:

Join BYJU'S Learning Program

A sphere of density d is allowed to fall in a liquid of density d/4. The acceleration of the body will be:

The correct option is B 3g4 Now,Force downward=mg=VdgNet force upward=Vdg4So,Net force dowanward=34Vdg=ma34Vdg=Vdaa=3g4

The correct option is B $\frac{3 g}{4}$

Now,
Force downward $= m g = V d g$
Net force upward $= \frac{V d g}{4}$
So,
Net force dowanward $= \frac{3}{4} V d g = m a$
$\frac{3}{4} V d g = V d a$
$a = \frac{3 g}{4}$