A sphere of mass 50g is suspended by a string in an electric field of intensity 5NC−1 acting vertically upward. If the charge on the sphere is 4×10−3C then the tension in the string is (g=10ms−2)
A
520×10−3N
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B
520×10−2N
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C
520N
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D
480×10−3N
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Solution
The correct option is D480×10−3N
From the FBD of the bob,
T+Fe=W
T+Eq=mg
T=mg−Eq
=(50×10−3×10)−(5×4×10−3)
=(500−20)10−3
T=480×10−3N
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Hence, (d) is the correct answer.