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Pure Rolling

A sphere of m...

Question

A sphere of mass $50 g m$ diameter $2 c m$ rolls without slipping with a velocity of $5$ cm/s.Calculate its total kinetic energy.

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Solution

Given,

$M a s s = 50 g, d = 2 c m, v = 5 c m / s$

So, $K E = \frac{1}{2} m v^{2} (1 + \frac{k^{2}}{r^{2}}) = \frac{1}{2} \times 50 \times 5^{2} (1 + \frac{2}{5}) = 875 e r g$

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