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Standard XII

Physics

Newton's Law of Gravitation

A sphere of m...

Question

A sphere of mass M and radius R₂ has a concentric cavity of radius R₁ as shown in figure. The force F exerted by the sphere on a particle of mass m located at a distance r from the centre of sphere varies as $(0 \leq r \leq \infty)$

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Solution

The correct option is B
$F = 0 w h e n 0 \leq r \leq R_{1}$ , because intensity is zero inside the cavity.
F increases when $R_{1} \leq r \leq R_{2}; F \propto \frac{1}{r^{2}} w h e n r > R_{2}$

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A sphere of mass M and radius R2 has a concentric cavity of radius R1 as shown in figure. The force F exerted by the sphere on a particle of mass m located at a distance r from the centre of sphere varies as (0≤r≤∞)

The correct option is B F=0 when 0≤r≤R1, because intensity is zero inside the cavity. F increases when R1≤r≤R2; F∝1r2 when r>R2

A sphere of mass M and radius R₂ has a concentric cavity of radius R₁ as shown in figure. The force F exerted by the sphere on a particle of mass m located at a distance r from the centre of sphere varies as $(0 \leq r \leq \infty)$

The correct option is B
$F = 0 w h e n 0 \leq r \leq R_{1}$ , because intensity is zero inside the cavity.
F increases when $R_{1} \leq r \leq R_{2}; F \propto \frac{1}{r^{2}} w h e n r > R_{2}$