You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Newton's Law of Gravitation

A sphere of m...

Question

A sphere of mass M and radius R₂ has a concentric cavity of radius R₁ as shown in figure. The force F exerted by the sphere on a particle of mass m located at a distance r from the centre of sphere varies as $(0 \leq r \leq \infty)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$F = 0 w h e n 0 \leq r \leq R_{1}$ , because intensity is zero inside the cavity.
F increases when $R_{1} \leq r \leq R_{2}; F \propto \frac{1}{r^{2}} w h e n r > R_{2}$

Suggest Corrections

Similar questions

A sphere of mass M and radius R₂ has a concentric cavity of radius R_{1 as} shown in figure. The force F exerted by the sphere on a particle of mass m located at a distance r from the center of sphere varies as (0 $\leq$ r $\leq$ ∞)

Q. A cavity of radius

\frac{R}{2}

is made inside a solid sphere of radius R. The centre of the cavity is located at a distance

\frac{R}{2}

from the centre of sphere . The gravitational force on a particle of mass m at a distance

\frac{R}{2}

from the centre of the sphere on the line joining both the centres of sphere and cavity is ( opposite to the centre of cavity) [ here g =

\frac{G M}{R^{2}}

where M is the mass of the sphere].

Q. A activity of radius

R / 2

is made inside a solid sphere of radius

R

. The centre of cavity is located at a distance

R / 2

from the centre of the sphere. The gravitational force on a particle of mass

^{'} m^{'}

at a distance

R / 2

from the centre of the sphere on the line joining both the centres of sphere and cavity is (opposite to the centre of cavity). [Here

g = G M / R^{2}

, where

M

is the mass of the sphere]

Q. A cavity of radius

R / 2

is made inside a solid sphere of radius

R

. The centre of the cavity is located at a distance

R / 2

from the centre of the sphere. The gravitational force on a particle of mass '

m

'at a distance

R / 2

from the centre of the sphere on the line joining both the centres of a sphere and cavity is - (opposite to the centre of gravity)
[Here

g = G M / R^{2}

, where

M

is the mass of the sphere]

Q. A solid sphere of mass

M

and radius

R

has a spherical cavity of radius

\frac{R}{2}

such that the centre of cavity is at a distance

\frac{R}{2}

from the centre of the sphere. The force of attraction that this sphere would exert on a particle of mass

m

which lies at a distance

d (> R)

from the centre of the solid sphere on the straight line joining the centre of the sphere and the center of cavity is

Join BYJU'S Learning Program

A sphere of mass M and radius R2 has a concentric cavity of radius R1 as shown in figure. The force F exerted by the sphere on a particle of mass m located at a distance r from the centre of sphere varies as (0≤r≤∞)

The correct option is B F=0 when 0≤r≤R1, because intensity is zero inside the cavity. F increases when R1≤r≤R2; F∝1r2 when r>R2

A sphere of mass M and radius R₂ has a concentric cavity of radius R₁ as shown in figure. The force F exerted by the sphere on a particle of mass m located at a distance r from the centre of sphere varies as $(0 \leq r \leq \infty)$

The correct option is B
$F = 0 w h e n 0 \leq r \leq R_{1}$ , because intensity is zero inside the cavity.
F increases when $R_{1} \leq r \leq R_{2}; F \propto \frac{1}{r^{2}} w h e n r > R_{2}$