A sphere of mass m is rolling on a frictionless surface (as shown in the figure) with a translation velocity v m/s. The sphere will climb on the inclined plane if v is
∴12Iω2+12mv2≥mgh
⇒12(25mr2)ω2+12mv2≥mgh
For pure rolling, v=rω
⇒15mv2+12mv2≥mgh⇒v≥√107gh
Why this question? Tips:- A rolling body contains rotational as well as translational kinetic energy. |