1
Question
A sphere of radius 1cm has potential of 8000 V ,then what will be energy density near its surface in J/m^3?
A sphere of radius 1cm has potential of 8000 V ,then what will be energy density near its surface in J/m^3?
Open in App
Solution
Answer: (B) 2.83 (J/m3)
Energy density = (1/2)∈0E2
= (1/2) × 8.86 × 10–12 × (v/r)2
= 4.43 × 10–12 × [(8000) / (10–2)]2
= 283.5 × 10–2
= 2.83 J/m3
Hope this helps :)
Answer: (B) 2.83 (J/m3)
Energy density = (1/2)∈0E2
= (1/2) × 8.86 × 10–12 × (v/r)2
= 4.43 × 10–12 × [(8000) / (10–2)]2
= 283.5 × 10–2
= 2.83 J/m3
Hope this helps :)
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
