197
Question
A sphere of radius 1cm has potential of 8000 V ,then what will be energy density near its surface in J/m^3?
A sphere of radius 1cm has potential of 8000 V ,then what will be energy density near its surface in J/m^3?
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Solution
Answer: (B) 2.83 (J/m3)
Energy density = (1/2)∈0E2
= (1/2) × 8.86 × 10–12 × (v/r)2
= 4.43 × 10–12 × [(8000) / (10–2)]2
= 283.5 × 10–2
= 2.83 J/m3
Hope this helps :)
Answer: (B) 2.83 (J/m3)
Energy density = (1/2)∈0E2
= (1/2) × 8.86 × 10–12 × (v/r)2
= 4.43 × 10–12 × [(8000) / (10–2)]2
= 283.5 × 10–2
= 2.83 J/m3
Hope this helps :)
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