A sphere of radius -a- subtends an angle 60 - at a point P- Then the distance of P from the centre of the sphere is-

The correct option is B 2 a [ cos 60^ 0 = a / op #160;; op= a /cos 60 ^ 0 #160; ...

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Standard XII

Mathematics

Definition of Ellipse

A sphere of r...

Question

A sphere of radius $^{'} a^{'}$ subtends an angle $60^{\circ}$ at a point $P$ . Then the distance of $P$ from the centre of the sphere is.

\frac{a}{\sqrt{3}}

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2 a

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\frac{a \sqrt{3}}{2}

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\frac{2 a}{\sqrt{3}}

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Solution

The correct option is B $2 a$
$\begin{matrix} cos 60^{0} = \frac{a}{o p} o p = \frac{a}{cos 60^{0}} = 2 a O p t i o n B i s c o r r e c t a n s w e r . \end{matrix}$

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A sphere of radius ′a′ subtends an angle 60∘ at a point P. Then the distance of P from the centre of the sphere is.

The correct option is B 2acos600=aopop=acos600=2aOptionBiscorrectanswer.

A sphere of radius $^{'} a^{'}$ subtends an angle $60^{\circ}$ at a point $P$ . Then the distance of $P$ from the centre of the sphere is.

The correct option is B $2 a$
$\begin{matrix} cos 60^{0} = \frac{a}{o p} o p = \frac{a}{cos 60^{0}} = 2 a O p t i o n B i s c o r r e c t a n s w e r . \end{matrix}$