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Question

A sphere of weight w is hanging against a wall as shown in Figure. Which of the relations is incorrect?
29361.PNG

A
¯¯¯¯T+¯¯¯¯¯¯W+¯¯¯¯¯N=0
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B
Tsinθ=N
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C
T=W/cosθ
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D
WN=T/cosθ
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Solution

The correct option is D WN=T/cosθ
Since the sphere is in equilibrium, resultant sum of all forces on it must add to 0. Hence option A is correct.

For vertical equilibrium, vertical component of tension must be equal to weight of the sphere. Hence option B is correct.

For horizontal equilibrium, horizontal component of tension must be equal to normal force from wall on the sphere. Hence option C is correct.

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