Question

A sphere rolls down on an inclined plane of inclination $\theta$. What is the acceleration as the sphere reaches bottom

• A. $\frac{5}{7}g\sin \theta$
• B. $\frac{3}{5}g\sin \theta$
• C. $\frac{2}{7}g\sin \theta$
• D. $\frac{2}{5}g\sin \theta$

Answer 1

The correct option is A $\frac{5}{7}g\sin \theta$

Acceleration (a) $=\frac{g\sin \theta }{1+\frac{K^2}{R^2}}=\frac{g\sin \theta }{1+\frac{2}{5}}=\frac{5}{7}g\sin \theta .$