CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A spherical ball of mass 1 kg moving with a uniform speed of 1 m/s collides symmetrically with two identical spherical balls of mass 1 kg each at rest touching each other. If the two balls move with 0.5m/s in two directions at the same angle of 60o with the direction of the first ball, the loss of kinetic energy on account of the collision is:

A
0.125 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.5 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.0 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.75 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.125 J
As per conservation of linear momentum in the direction of motion of first ball,
1×1=1×0.5cos60+1×0.5cos60+1×V which gives V=0. 5
So final velocity of the first ball = 0.5 m/s
Loss of kinetic energy =Initial kinetic energy - Final kinetic energy
=12×1×12 - 12×1×0.52 - 12×1×0.52-12×1×0.52
=0.5-0.375=0.125J

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conservation of Momentum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon