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Question

A spherical ball of mass 20 kg is stationary at the top of a hill of height 100 m. It rolls down a smooth surface to the ground and then climbs up another hill of height 30 m and finally rolls down to a horizontal base at a height 20 m above the ground. The velocity attained by the ball is:

A
40 ms1
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B
20 ms1
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C
10 ms1
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D
10 30 ms1
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Solution

The correct option is B 40 ms1
For the potential energy, only the difference between the initial and final points count.

So this difference is 10020=80 m

Conservation of energy

12mv2=mgh

0.5v2=10×80

v=40 m/s

Option A.

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