A spherical black body with a radius of $12 c m$ radiates $450 W$ power at $500 K$ . If the radius were halved and the temperature doubled, the power radiated in watt would be:

1800

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

225

No worries! We‘ve got your back. Try BYJU‘S free classes today!

450

No worries! We‘ve got your back. Try BYJU‘S free classes today!

900

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $1800$
$Q =\in σ A T^{4}$
If $r_{2} = \frac{r_{1}}{2} a n d A_{2} = \frac{A_{1}}{4} (∵ A \propto r^{2})$
& $T_{2} = 2 T_{1}$
$\frac{Q_{2}}{Q_{1}} = \frac{(A_{1} / 4) (16 T_{1}^{4})}{A_{1} T^{4}} = 4$
$Q_{2} = 4 Q_{1} = 4 \times 450 = 1800$

Suggest Corrections

Similar questions

A spherical black body of radius 12 cm radiates 450 W power at 500 K. If the radius were halved and the temperature doubled, the power radiated in watt would be

A spherical black body with a radius of 12 cm radiates 450 W power at 50 K. If the radius was halved and the temperature doubled, the power radiated in watt would be:

A spherical black body of radius 12cm radiates 450W power of 500k. If the radius is halved and the temperature is doubled the power radiated in watts would be

A spherical black body of radius 12 cm radiates 450 W power at 500 K. If the radius were halved and the temperature doubled, the power radiated would be

Join BYJU'S Learning Program

A spherical black body with a radius of 12 cm radiates 450 W power at 500 K. If the radius were halved and the temperature doubled, the power radiated in watt would be:

The correct option is A 1800Q=∈σAT4If r2=r12 and A2=A14(∵A∝r2)& T2=2T1Q2Q1=(A1/4)(16T41)A1T4=4Q2=4Q1=4×450=1800

A spherical black body with a radius of $12 c m$ radiates $450 W$ power at $500 K$ . If the radius were halved and the temperature doubled, the power radiated in watt would be:

The correct option is A $1800$
$Q =\in σ A T^{4}$
If $r_{2} = \frac{r_{1}}{2} a n d A_{2} = \frac{A_{1}}{4} (∵ A \propto r^{2})$
& $T_{2} = 2 T_{1}$
$\frac{Q_{2}}{Q_{1}} = \frac{(A_{1} / 4) (16 T_{1}^{4})}{A_{1} T^{4}} = 4$
$Q_{2} = 4 Q_{1} = 4 \times 450 = 1800$