A spherical body having radius r is radiating energy Q at a given temperature. If its radius is doubled then for same time, energy radiated will be
A
12Q
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B
14Q
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C
2Q
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D
4Q
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Solution
The correct option is D4Q We know, emissive power, E=QAt where Q is energy emitted, A is the surface area of body and t is time. ⇒Q=EAt ⇒Q∝A[ material and time are same ] ⇒Q∝r2[A=4πr2] If radius is doubled then energy emitted will be 4 times the initial value.