A spherical body having radius r is radiating energy Q at a given temperature, in a particular time. If its radius is doubled then for same time and temperature, energy radiated will be
A
12Q
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
14Q
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2Q
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4Q
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D4Q We know, emissive power, E=QAt
where Q is energy emitted, A is the surface area of body and t is time. ⇒Q=EAt ⇒Q∝A[ material and time are same ] ⇒Q∝r2[A=4πr2]
If radius is doubled then energy emitted will be 4 times the initial value.