Question

A spherical body of radius R consists of a fluid of constant density and is in equilibrium under its own gravity. If$P\left(r\right)$ is the pressure at $r(r<R)$, then the correct option(s) is(are)?

• A. $P(r=0)=0$
• B. $\frac{P(r=3R/4)}{P(r=2R/3)}=\frac{63}{80}$
• C. $\frac{P(r=3R/5)}{P(r=2R/5)}=\frac{16}{21}$
• D. $\frac{P(r=R/2)}{P(r=R/3)}=\frac{20}{27}$

Answer 1

Answer: (B), (C)

The correct options are
B $\frac{P(r=3R/4)}{P(r=2R/3)}=\frac{63}{80}$
C $\frac{P(r=3R/5)}{P(r=2R/5)}=\frac{16}{21}$