A spherical capacitor consists of two concentric spherical conductors of inner one of radius R1 maintained at potential V1 and the outer one of radius R2 at potential V2. The potential at a point p at a distance x from the centre (R2>x>R1) is:
A
V1−V2R2−R1(x−R1)
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B
V1R1(R2−x)+V2R2(x−R1)x(R2−R1)
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C
V1+V2xR2−R1
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D
V1+V2R2+R1x
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Solution
The correct option is AV1R1(R2−x)+V2R2(x−R1)x(R2−R1) Let q1 and q2 be the charges on inner and outer sphere respectively. Here, V1=k[q1R1+q2R2] or V1=k[q1R2+q2R1R1R2] or q2=V1R1R2kR1−q1R2R1=V1R2k−q1R2R1 and V2=k[q1+q2R2] or V2R2=k[q1+q2] or V2R2k=[q1+V1R2k−q1R2R1] or V2R2k−V1R2k=q1[R1−R2R1] or q1=(V2−V1)R1R2k(R1−R2) now , q2=V1R2k−(V2−V1)R1R2k(R1−R2)×R2R1 now, Vx=k[q1x+q2R2] putting the value of q1 and q2 , we get Vx=V1R1(R2−x)+V2R2(x−R1)(R2−R1)x